A.Zero✓
B.minimum
C.maximum
D.infinite
Correct answer: A
Straight to the answer: option A, at the neutral axis bending stress is zero by definition — fibres there neither compress nor stretch
Read full explanation →MPSC General2017EnglishOfficial Set A Key
RTO AMVI Mains 2017 — Mechanical / Automobile Engineering — Question Paper with Answer Key & Explanations
Practice the RTO AMVI Mains 2017 — Mechanical / Automobile Engineering previous-year paper online for free. This paper has 150 questions, each with the official Set A answer key and a plain-language explanation. It is available in English exactly as it appeared in the official Maharashtra Public Service Commission paper. Sign in on the home page to attempt the full paper with instant scoring.
150
Questions
2
Subjects
2017
Exam Year
1
Languages
Subject-wise breakdown
Mechanical & Automobile120 questions
Mechanical Engineering30 questions
Sample questions with answers
A preview from this paper. Sign in to attempt all 150 questions with instant scoring.
A.Ix = 0.055 r⁴✓
B.Ix = 0.11 r⁴
C.Iy = 0.4 r⁴
D.None of these
Correct answer: A
The right pick is option A; quarter-circle I about centroidal x-axis is Ix ≈ 0.055 r⁴ from standard moment-of-inertia tables MPSC revisits this mechanical/auto fact in later AMVI cycles.
Read full explanation →A.δL = PdL / (2tE)✓
B.δL = PdL / (tE)
C.δL = (PdL / 2tE)(1 − 2μ)
D.None of these
Correct answer: A
The verified answer here is option A: longitudinal strain in a thin cylinder under internal pressure gives δL = PdL/(2tE) when end effects are neglected
Read full explanation →A.45°
B.30°
C.60°
D.90°✓
Correct answer: D
The examiner has marked option D, where major and minor principal planes are orthogonal, so the angle between them is 90° Re-read the stem once before finalising — close distractors are common in AMVI papers.
Read full explanation →A.400 N/mm²
B.200 N/mm²✓
C.100 N/mm²
D.150 N/mm²
Correct answer: B
You want option B on this one — bending stress σ = E·y/R with y = t/2 and R = 10 m gives about 200 N/mm² for the given steel plate
Read full explanation →A.√2
B.2✓
C.0.5
D.4
Correct answer: B
Reading the stem carefully, option B fits because Euler critical load ratio for fixed-fixed vs fixed-hinged ends is 4:2, i.e. √2 MPSC revisits this mechanical/auto fact in later AMVI cycles.
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This Maharashtra Public Service Commission paper follows the standard objective (MCQ) format with one-fourth negative marking, set in parallel English and Marathi. Every question below is transcribed from the official paper and paired with the official Set A answer key.
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